190 lines
2.8 KiB
Go
190 lines
2.8 KiB
Go
// grug math is an unbounded precision math library for integers. It is not designed to be performant in any means. But as an example of how one works.
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package math
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import "strconv"
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type Number []rune
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func NewNumber() *Number {
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return &Number{}
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}
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func (*Number) FromString(s string) *Number {
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for _, a := range s {
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if !(a >= '0' && a <= '9') {
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return nil
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}
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}
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var n Number = []rune(s)
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i:=0
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for range n[:len(n)-1] {
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if n[i] == 0 || n[i] == '0' {
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i++
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} else {
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break
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}
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}
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n = n[i:]
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return &n
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}
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func (*Number) FromInt(i int) *Number {
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s := strconv.Itoa(i)
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var n Number = []rune(s)
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return &n
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}
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func (n *Number) String() string {
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if n == nil || len(*n) == 0 {
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return "NaN"
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}
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return string(*n)
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}
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func (n *Number) Add(a *Number) *Number {
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if n == nil || a == nil {
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return nil
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}
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lenN, lenA := len(*n), len(*a)
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sum := make(Number, max(lenN, lenA)+1)
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for i := range sum[:len(sum)-1] {
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ii := len(sum) - i - 1
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switch {
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case lenN == lenA:
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j := (*n)[lenN-i-1]
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k := (*a)[lenA-i-1]
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sum[ii-1], sum[ii] = add(j, k, sum[ii])
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case lenN > lenA:
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j := (*n)[lenN-i-1]
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k := '0'
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if i < lenA {
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k = (*a)[lenA-i-1]
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}
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sum[ii-1], sum[ii] = add(j, k, sum[ii])
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case lenN < lenA:
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j := '0'
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if i < lenN {
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j = (*n)[lenN-i-1]
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}
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k := (*a)[lenA-i-1]
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sum[ii-1], sum[ii] = add(j, k, sum[ii])
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}
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}
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// Trim the extra 0 if present
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if sum[0] == 0 || sum[0] == '0' {
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sum = sum[1:]
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}
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return &sum
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}
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func (n *Number) Sub(s *Number) *Number {
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if n == nil || s == nil {
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return nil
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}
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lenN, lenA := len(*n), len(*s)
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sum := make(Number, max(lenN, lenA)+1)
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for i := range sum[:len(sum)-1] {
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ii := len(sum) - i - 1
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switch {
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case lenN == lenA:
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j := (*n)[lenN-i-1]
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k := (*s)[lenA-i-1]
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c := '0'
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if i+1 < lenN {
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c = (*n)[lenN-i-2]
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}
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sum[ii-1], sum[ii] = sub(j, k, c)
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case lenN > lenA:
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j := (*n)[lenN-i-1]
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k := '0'
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if i < lenA {
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k = (*s)[lenA-i-1]
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}
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c := '0'
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if i+1 < lenN {
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c = (*n)[lenN-i-2]
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}
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sum[ii-1], sum[ii] = sub(j, k, c)
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if i+1 < lenN {
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(*n)[lenN-i-2] =sum[ii-1]
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}
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case lenN < lenA:
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j := '0'
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if i < lenN {
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j = (*n)[lenN-i-1]
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}
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k := (*s)[lenA-i-1]
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c := '0'
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if i+1 < lenN {
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c = (*n)[lenN-i-2]
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}
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sum[ii-1], sum[ii] = sub(j, k, c)
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}
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}
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// Trim the extra 0 if present
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i:=0
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for range sum[:len(sum)-1] {
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if sum[i] == 0 || sum[i] == '0' {
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i++
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} else {
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break
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}
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}
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sum = sum[i:]
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return &sum
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}
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func friends(r rune) (int32, int32) {
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return 1, 10 - int32(r-'0')
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}
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func add(a, b, c rune) (rune, rune) {
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up, dn := friends(b)
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if c == 0 {
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c = '0'
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}
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a = a + c - '0'
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if a-dn < '0' {
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return '0', a + b - '0'
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}
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return c + up, a - dn
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}
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func sub(a, b, c rune) (rune, rune) {
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dn, up := friends(b)
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if c == 0 {
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c = '0'
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}
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if a+up > '9' {
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return c, a - b + '0'
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}
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return c - dn, a + up
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}
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